我算出两个霍普夫分岔点为:
first point found
tangent vector to first point found
label = H , x = ( 0.073637 0.005422 0.003067 0.005892 )
First Lyapunov coefficient = -7.371038e+001
label = H , x = ( 0.332767 0.110734 0.002296 0.167406 )
First Lyapunov coefficient = -3.494008e+001
elapsed time = 15.9 secs
npoints curve = 300
可是画分岔图的时候总是报错: time step too small。 烦请高手指点一下, 最好能给画一下,我需要的是x,z 以c为控制参数的分岔图, 并且需要系统周期随c 的变化关系
我之前也看过一点matcont,尝试画了下分岔图,但是看不懂怎么回事,不过到没遇到你说的这种错误,你是怎么画的呢,我是按着里面画的,不知对你是否有用
Matcont : A Matlab package for dynamical systems with applications to neural activity