Inner matrix dimensions must agree帮帮下?

hljtlhs

我的这个程序哪错了。急帮看看。怎么就是不行，。
>> theta1_U=2.7925; theta2_L=-1.7628; theta2_U=1.7628;
>> theta3_L=-1.8326; theta3_U=1.8326; theta4_L=-2.7925; theta4_U=2.7925;
>> theta5_L=-2.0944; theta5_U=2.0944; theta6_L=-18.8495; theta6_U=18.8495;
>> L3=315; L2=287; Lt=226;
>> B=zeros(5000,1); A=zeros(5000,1); C=zeros(5000,1); i=1;
>> while i<=5000; rand=0:0.1:1;
theta1_i=theta1_L+(theta1_U-theta1_L)*rand;
theta2_i=theta1_i+(theta2_U-theta2_L)*rand;
theta3_i=theta2_i+(theta3_U-theta3_L)*rand;
theta4_i=theta3_i+(theta4_U-theta4_L)*rand;
theta5_i=theta4_i+(theta5_U-theta5_L)*rand;
theta6_i=theta5_i+(theta6_U-theta6_L)*rand;
P_y=-((-(-sin(theta1_i)*sin(theta2_i)*sin(theta3_i)+sin(theta1_i)*cos(theta2_i)*cos(theta3_i))*sin(theta4_i)+cos(theta1_i)*cos(theta4_i))*sin(theta5_i)-(sin(theta1_i)*sin(theta2_i)*cos(theta3_i)+sin(theta1_i)*cos(theta2_i)*sin(theta3_i))*cos(theta5_i))*Lt-(-sin(theta1_i)*sin(theta2_i)*cos(theta3_i)-sin(theta1_i)*cos(theta2_i)*sin(theta3_i))*L3+sin(theta1_i)*sin(theta2_i)*L2;
P_z=-(-(-cos(theta2_i)*sin(theta3_i)-sin(theta2_i)*cos(theta3_i))*sin(theta4_i)*sin(theta5_i)-(cos(theta2_i)*cos(theta3_i)-sin(theta2_i)*sin(theta3_i))*cos(theta5_i))*Lt-(-cos(theta2_i)*cos(theta3_i)+sin(theta2_i)*sin(theta3_i))*L3+cos(theta2_i)*L2;
P_x=-((-(-cos(theta1_i)*sin(theta2_i)*sin(theta3_i)+cos(theta1_i)*cos(theta2_i)*cos(theta3_i))*sin(theta4_i)-sin(theta1_i)*cos(theta4_i))*sin(theta5_i)-(cos(theta1_i)*sin(theta2_i)*cos(theta3_i)+cos(theta1_i)*cos(theta2_i)*sin(theta3_i))*cos(theta5_i))*Lt-(-cos(theta1_i)*sin(theta2_i)*cos(theta3_i)-cos(theta1_i)*cos(theta2_i)*sin(theta3_i))*L3+cos(theta1_i)*sin(theta2_i)*L2;
A(i,1)=P_x; B(i,1)=P_y; C(i,1)=P_z; i=i+1;
end;
??? Error using ==> mtimes
Inner matrix dimensions must agree.
急啊。哪位有高手帮帮吧:'( :'( :'(

我这个到theta6都对的。一加上P_y=。。的就不对了。end 后就会说错了为什么啊，是不是P_y=后面的试子有错啊。帮帮吧:@( :@(

还是while   有的不对

[ 本帖最后由 ChaChing 于 2009-5-6 16:47 编辑 ]

sogooda

初到本版，建议先看看进版必读。
btw：请使用合适的标题反应帖子的内容。

sigma665

??? Error using ==> mtimes
Inner matrix dimensions must agree.

*换成.*