大家帮我看一下那里不正确

dayu7973

计算一根齿轮轴的临界转速，命令流如下：
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
finish
/clear
/title,3D model analysis
/filname,chilunzhou,1
/prep7
!钢
mp,EX,1,2.1e+11
mp,DENS,1,7850
mp,PRXY,1,0.3

! shaft
et,1,188,,,2
sectype,1,beam, CTUBE
secdata,0.100,0.160,32
sectype,2,beam, CTUBE
secdata,0.100,0.260,32
sectype,3,beam, CTUBE
secdata,0.100,0.400,32

! bearings
et,2,214,,1,1
r,4,2.59e+8,7.56e+8,-2.44e+7,6.52e+8,3.31e+5,19.12e+5,4.27e+5,4.27e+5
r,5,2.19e+8,5.32e+8,-4.08e+7,5.32e+8,3.12e+5,15.53e+5,3.69e+5,3.69e+5
r,6,1.36e+7,1.62e+7,-1.84e+7,6.89e+7,0.55e+5,1.99e+5,0.20e+5,0.20e+5
! nodes
n,1 !
n,9 ,0.570 !
fill,1,9,7,2,1
n,25 ,1.665
fill,9,25,15,10,1
n,29 ,1.865
fill,25,29,3,26,1

! bearings second nodes

n,101,0,0.15
n,109,0.570,0.15
n,125,1.665,0.15

! components elements
type,1
secn,2
e,1,2
egen,8,1,1

type,1
secn,1
e,9,10
egen,18,1,9

type,1
secn,3
e,27,28
e,28,29
cm,Spool,elem
allsel

! bearings
type,2
real,4
e,1,101
real,5
e,9,109
real,6
e,25,125

! boundary conditions
d,all,ux,,,,,rotx
d,101,all
d,109,all
d,125,all

/SOLU
antype,modal
CMACEL,Spool, ,9.8, ,
modopt,qrdamp,6,,,,on
coriolis,on,,,on
cmomega,Spool,0.
mxpand,6
solve
cmomega,spool,1256. !rad/s
mxpand,6
solve
finish
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
结果总是不正确，不知道问题出在哪里！
还有就是Results Summary里面的结果该怎样取舍？
请大家多多指教！

16443

大致看了一下。
你这只是个模态分析，而且你的轴承支撑好像没起作用。


[ 本帖最后由 16443 于 2008-12-8 12:19 编辑 ]

dayu7973

可是问题出在哪里呢？很是费解