内网用户，下不到emd的相关程序，请大家帮忙

lierr

内网用户，下不到emd的相关程序，请大家帮忙

邮箱lh900@yohoo.cn,给我发一份吧，如果有相关学习资料也给我发一下吧！

感谢ing

lierr

emd的包我弄到了，现在还缺少这个：

tftb-0.1.tar.gz压缩包

看到的兄弟帮帮忙啊！！！

lierr

怎么没人回复啊，我缺少一个instfreq 函数，有的话，给我发一个吧...

zhangnan3509

function [fnormhat,t]=instfreq(x,t,L,trace);
%INSTFREQ Instantaneous frequency estimation.
%        [FNORMHAT,T]=INSTFREQ(X,T,L,TRACE) computes the instantaneous
%        frequency of the analytic signal X at time instant(s) T, using the
%        trapezoidal integration rule.
%        The result FNORMHAT lies between 0.0 and 0.5.
%
%        X : Analytic signal to be analyzed.
%        T : Time instants                (default : 2:length(X)-1).
%        L : If L=1, computes the (normalized) instantaneous frequency
%            of the signal X defined as angle(-X(T+1)*conj(X(T-1)) ;
%            if L>1, computes a Maximum Likelihood estimation of the
%            instantaneous frequency of the deterministic part of the signal
%            blurried in a white gaussian noise.
%            L must be an integer               (default : 1).
%        TRACE : if nonzero, the progression of the algorithm is shown
%                                        (default : 0).
%        FNORMHAT : Output (normalized) instantaneous frequency.
%        T : Time instants.
%
%        Examples :
%         x=fmlin(70,0.05,0.35,25); [instf,t]=instfreq(x); plot(t,instf)
%         N=64; SNR=10.0; L=4; t=L+1:N-L; x=fmsin(N,0.05,0.35,40);
%         sig=sigmerge(x,hilbert(randn(N,1)),SNR);
%         plotifl(t,[instfreq(sig,t,L),instfreq(x,t)]); grid;
%         title ('theoretical and estimated instantaneous frequencies');
%
%        See also  KAYTTH, SGRPDLAY.

%        F. Auger, March 1994, July 1995.
%        Copyright (c) 1996 by CNRS (France).
%
%        ------------------- CONFIDENTIAL PROGRAM --------------------
%        This program can not be used without the authorization of its
%        author(s). For any comment or bug report, please send e-mail to
%        f.auger@ieee.org

if (nargin == 0),
error('At least one parameter required');
end;
[xrow,xcol] = size(x);
if (xcol~=1),
error('X must have only one column');
end

if (nargin == 1),
t=2:xrow-1; L=1; trace=0.0;
elseif (nargin == 2),
L = 1; trace=0.0;
elseif (nargin == 3),
trace=0.0;
end;

if L<1,
error('L must be >=1');
end
[trow,tcol] = size(t);
if (trow~=1),
error('T must have only one row');
end;

if (L==1),
if any(t==1)|any(t==xrow),
  error('T can not be equal to 1 neither to the last element of X');
else
  fnormhat=0.5*(angle(-x(t+1).*conj(x(t-1)))+pi)/(2*pi);
end;
else
H=kaytth(L);
if any(t<=L)|any(t+L>xrow),
  error('The relation L<T<=length(X)-L must be satisfied');
else
  for icol=1:tcol,
   if trace, disprog(icol,tcol,10); end;
   ti = t(icol); tau = 0:L;
   R = x(ti+tau).*conj(x(ti-tau));
   M4 = R(2:L+1).*conj(R(1:L));
   
   diff=2e-6;
   tetapred = H * (unwrap(angle(-M4))+pi);
   while tetapred<0.0 , tetapred=tetapred+(2*pi); end;
   while tetapred>2*pi, tetapred=tetapred-(2*pi); end;
   iter = 1;
   while (diff > 1e-6)&(iter<50),
    M4bis=M4 .* exp(-j*2.0*tetapred);
    teta = H * (unwrap(angle(M4bis))+2.0*tetapred);
    while teta<0.0 , teta=(2*pi)+teta; end;
    while teta>2*pi, teta=teta-(2*pi); end;
    diff=abs(teta-tetapred);
    tetapred=teta; iter=iter+1;
   end;
   fnormhat(icol,1)=teta/(2*pi);
  end;
end;
end;

版里贴了很多次了 这个程序。我自己也发过这个帖子。而且楼主注意置顶贴的提示啊

lierr

谢谢楼上的，都怪自己找的不仔细！

asdf229955

我也下来看看