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三角平台受一地震谱激励,求应力分布和支反力
基本过程:
1、建模
2、求模态解
3、求谱解
4、扩展模态
5、模态合并
6、观察结果
- /PREP7 !建模
- ET,1,BEAM189
- ET,2,SHELL93
- R,1,0.01, , , , , ,
- MP,EX,1,210e9
- MP,PRXY,1,0.3
- MP,DENS,1,7850
- SECTYPE, 1, BEAM, RECT, secA, 0
- SECOFFSET, CENT
- SECDATA,0.005,0.008,0,0,0,0,0,0,0,0
- K, ,-0.5,,,
- K, ,0.5,,,
- K, ,,,1,
- K, ,,1,1,
- K, ,-0.5,1,,
- K, ,0.5,1,,
- K, ,,,0.5,
- A,4,5,6
- LSTR, 1, 5
- LSTR, 3, 4
- LSTR, 2, 6
- LSEL,S,LINE,,4,6
- LATT,1,1,1, , 7, ,1
- LSEL, , , ,ALL
- LESIZE,ALL, , ,10, , , , ,1
- LMESH,4,6
- TYPE, 2
- MSHAPE,0,2D
- MSHKEY,1
- AMESH,1
- FINISH
- /SOL !取前十阶模态
- ANTYPE,2
- MODOPT,LANB,10
- KSEL,S,KP,,1,3
- DK,ALL, , , ,0,ALL, , , , , ,
- SOLVE
- FINISH
- /SOL !谱分析
- ANTYPE,8
- SPOPT,SPRS,10,1
- SVTYP,3
- SED,0,1,0, !给出激励方向
- FREQ,0.25,1.34,6.73,14.6,28.9,0,0,0,0 !激励谱
- SV,0,0.00073,0.00016,0.00034,0.00034,0.00052,
- SOLVE
- FINISH
- /SOL !扩展模态
- ANTYPE,2
- EXPASS,1
- MXPAND,10,0,0,1,0.001,
- SOLVE
- FINISH
- /SOL !模态合并
- ANTYPE,8
- SRSS,0.001,DISP
- SOLVE
- /POST1 !观察结果
- SET,LIST
- /INPUT,,mcom
- PRRSOL,F
- FINISH
复制代码
来源:aoxue
[ 本帖最后由 yejet 于 2006-9-17 10:16 编辑 ] |