求解方程的问题
A=; B=; C=A+t×B=C
求t （t是一个实数；A、B、C是实数矩阵）
怎么求解t啊？用solve不能做啊。 这个移项不就解了吗？ 最小二乘即可 最小二乘法？用这个lsqnonlin命令？
移项之后，分解成若干个小方程求解吗？我想用个有效率点的方法。 A=; B=; C=;
B\(C-A) \
Backslash or matrix left division. If A is a square matrix, A\B is roughly the same as inv(A)*B, except it is computed in a different way. If A is an n-by-n matrix and B is a column vector with n components, or a matrix with several such columns, then X = A\B is the solution to the equation AX = B. A warning message is displayed if A is badly scaled or nearly singular. See the reference page for mldivide for more information.
If A is an m-by-n matrix with m ~= n and B is a column vector with m components, or a matrix with several such columns, then X = A\B is the solution in the least squares sense to the under- or overdetermined system of equations AX = B. The effective rank, k, of A is determined from the QR decomposition with pivoting (see Algorithm for details). A solution X is computed that has at most k nonzero components per column. If k < n, this is usually not the same solution as pinv(A)*B, which is the least squares solution with the smallest norm .
谢谢啦。
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