combi214单元后怎么定义实常数
选择了 combi214单元后怎么定义实常数 你是用classic分析的吗 参考combi214单元翻译回复 2 # haobaobaos 的帖子
不是 我用的是ansys 做转子动力学分析 选择了 combi214 就无法定义实常数了 就不能仔细点看看help文档，有在这里发帖的时间早就看完了。 可是 在ansys 的帮助文件里有这么一个例子/batch,list
/title, twin spools - unbalance (inner spool) response
/PREP7
mp,EX,1,2.1e+11
mp,DENS,1,7800
mp,PRXY,1,0.3
! shaft
et,1,188,,,2
sectype,1,beam,csolid
secdata,0.01524,32
sectype,2,beam,ctube
secdata,0.0254,0.03048,32
! disks
et,2,21
r,3,10.51,10.51,10.51,8.59e-2,4.295e-2,4.295e-2
r,4,7.01 ,7.01 ,7.01 ,4.29e-2,2.145e-2,2.145e-2
r,5,3.5,3.5,3.5,2.71e-2,1.355e-2,1.355e-2
r,6,7.01 ,7.01 ,7.01 ,6.78e-2,3.390e-2,3.390e-2
! bearings
et,3,214,,1
r,7 ,2.63e+7 ,2.63e+7
r,8 ,1.75e+7 ,1.75e+7
r,9 ,0.875e+7,0.875e+7
r,10,1.75e+7 ,1.75e+7
! nodes
n,1
n,2 ,0.0762
n,3 ,0.1524
n,4 ,0.2413
n,5 ,0.32385
n,6 ,0.4064
n,7 ,0.4572
n,8 ,0.508
n,9 ,0.1524
n,10,0.2032
n,11,0.2794
n,12,0.3556
n,13,0.4064
! bearings second nodes
n,101, ,0.05
n,108,0.508 ,0.05
n,109,0.1524,0.05
! components elements
type,1
secn,1
e,1,2
egen,7,1,1
type,2
real,3
e,2
real,6
e,7
cm,inSpool,elem
type,1
secn,2
e,9,10
egen,4,1,10
type,2
real,4
e,10
real,5
e,12
esel,u,,,inSpool
cm,outSpool,elem
allsel
! bearings
type,3
real,7
e,1,101
real,8
e,9,109
real,9
e,6,13
real,10
e,8,108
! boundary conditions
d,all,ux,,,,,rotx
d,101,all
d,108,all
d,109,all
! unbalance forces (eccentric mass * radius)
f0 = 70e-6
f,7,fy,f0
f,7,fz,,-f0
fini
/SOLU
antype,harmic
synchro,,inSpool
nsubst,500
harfrq,,14000/60! implicitly defines OMEGA for Coriolis calculation
kbc,1
dmprat,0.01
cmomega,inSpool,100.
cmomega,outSpool,150.
coriolis,on,,,on
solve
fini
! output: amplitude at nodes 7 and 12 as a function of the frequency
/POST26
nsol,2,7,U,Y,UY
nsol,3,7,U,Z,UZ
realvar,4,2,,,UYR
realvar,5,3,,,UZR
prod,6,4,4,,UYR_2
prod,7,5,5,,UZR_2
add,8,6,7,,UYR_2+UZR_2
sqrt,9,8,,,AMPL7
!
nsol,2,12,U,Y,UY
nsol,3,12,U,Z,UZ
realvar,4,2,,,UYR
realvar,5,3,,,UZR
prod,6,4,4,,UYR_2
prod,7,5,5,,UZR_2
add,8,6,7,,UYR_2+UZR_2
sqrt,10,8,,,AMPL12
!
/gropt,logy,1
/yrange,1.e-7,1.e-3
plvar,9,10
fini
! output: orbit plot at the given frequency
/POST1
set,1,262
/view,,1,1,1
plorb
! output: animation of the whirl at the given frequency
SET,1,500
!reset for subsequent post processing
eshape,1
/gline,,-1
plnsol,u,sum
anharm
et,3,214,,1
r,7 ,2.63e+7 ,2.63e+7
r,8 ,1.75e+7 ,1.75e+7
r,9 ,0.875e+7,0.875e+7
r,10,1.75e+7 ,1.75e+7
这不就是定义的实常数吗 我看了 没看不懂 你给指点指点
回复 9 # 尚慧娟 的帖子
现在我明白了
回复 7 # 尚慧娟 的帖子
这是ansys12的帮助文档吗？ 尚慧娟 发表于 2010-12-6 12:10 static/image/common/back.gif
可是 在ansys 的帮助文件里有这么一个例子/batch,list
/title, twin spools - unbalance (inner spool) re ...
回复--学习--那份--走人！
呵呵，谢谢啦，找了很久在这终于找到214单元的中文翻译，还有命令流例子，不错。
尚慧娟 发表于 2010-12-6 09:55 static/image/common/back.gif
选择了 combi214 就无法定义实常数了
不好意思啊，我也遇到了这个问题，但是我是新手，命令流压根不懂，我也是在选择了combi214之后，GUI无法定义实常数，不知道现在你是怎么处理的
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