lhwseu 发表于 2008-7-12 09:11

KEYOPT(1) = 0 (default)是什么意思?

If KEYOPT(1) = 0 (default), the element is a rigid link with two nodes and three degrees of freedom at each node (UX, UY, UZ). If KEYOPT(1) = 1, the element is a rigid beam with two nodes and six degrees of freedom at each node (UX, UY, UZ, ROTX, ROTY, ROTZ).ANSYS的帮助文件里有上面一段,不知道KEYOPT(1) = 0 (default), 和KEYOPT(1) = 1分别是什么意思,请高手赐教,我是新手.

xsdcaifu 发表于 2008-7-13 17:51

KEYOPT(1) 为0是2节点杆单元,每个节点有3个平动自由度
KEYOPT(1) 为1是2节点梁单元,每个节点有6个自由度(3个平动,3个转动)

lhwseu 发表于 2008-7-14 15:42

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谢谢.KEYOPT是那几个单词的缩写吗?
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