这个条件判断是多余的吗？
while SD > 0.3% 找极值点
d = diff(h);
% approximate derivative
maxmin = [];
for i=1:N-2
if d(i)==0
% we are on a zero
maxmin = ;
elseif sign(d(i))~=sign(d(i+1))
% we are straddling a zero so
maxmin = ;
% define zero as at i+1 (not i)
end
end
if size(maxmin,2) < 2
% 极值点数目小于2个跳出循环
break
%(maxmin,2)中的2代表列数即极值点数
end
% divide maxmin into maxes and mins
if maxmin(1)>maxmin(2)
% first one is a max not a min
maxes = maxmin(1:2:length(maxmin));
mins
= maxmin(2:2:length(maxmin));
else
% is the other way around
maxes = maxmin(2:2:length(maxmin));
mins
= maxmin(1:2:length(maxmin));
end
% 极值点的位置信息
maxes = ;
mins
= [1 mins
N];
这个程序，其中请主要关注这两个地方
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for i=1:N-2
if d(i)==0
% we are on a zero
maxmin = ;
elseif sign(d(i))~=sign(d(i+1))
% we are straddling a zero so
maxmin = ;
% define zero as at i+1 (not i)
end
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if maxmin(1)>maxmin(2)
% first one is a max not a min
maxes = maxmin(1:2:length(maxmin));
mins
= maxmin(2:2:length(maxmin));
else
% is the other way around
maxes = maxmin(2:2:length(maxmin));
mins
= maxmin(1:2:length(maxmin));
end
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请问这个判断maxmin(1)>maxmin(2) 是不是多余的？
[ 本帖最后由 eight 于 2007-5-5 11:21 编辑 ] 这个判断maxmin(1)>maxmin(2)条件是不是恒为真？下面的程序每次都执行
maxes = maxmin(1:2:length(maxmin));
mins
= maxmin(2:2:length(maxmin));
这两句，但对求包络结果没有影响，因此可以简化只有这两句
maxes = maxmin(1:2:length(maxmin));
mins
= maxmin(2:2:length(maxmin));
不知我这样分析对不对？ 怎么没有人看一下呢？
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