xcsyb 发表于 2006-6-12 15:58

[求助]请问哪位有分数阶FFT的程序

谢谢!

chuxidahai 发表于 2006-6-15 19:45

11

我也要

风花雪月 发表于 2006-6-15 20:01

回复:(xcsyb)[求助]请问哪位有分数阶FFT的程序

<P>我这里有个matlab写的<BR><BR></P><PRE>function Faf = frft(f, a)
% The fast Fractional Fourier Transform
% input: f = samples of the signal
%      a = fractional power
% output: Faf = fast Fractional Fourier transform
error(nargchk(2, 2, nargin));
f = f(:);
N = length(f);
shft = rem((0:N-1)+fix(N/2),N)+1;
sN = sqrt(N);
a = mod(a,4);
% do special cases
if (a==0), Faf = f; return; end;
if (a==2), Faf = flipud(f); return; end;
if (a==1), Faf(shft,1) = fft(f(shft))/sN; return; end
if (a==3), Faf(shft,1) = ifft(f(shft))*sN; return; end
% reduce to interval 0.5 &lt; a &lt; 1.5
if (a&gt;2.0), a = a-2; f = flipud(f); end
if (a&gt;1.5), a = a-1; f(shft,1) = fft(f(shft))/sN; end
if (a&lt;0.5), a = a+1; f(shft,1) = ifft(f(shft))*sN; end
% the general case for 0.5 &lt; a &lt; 1.5
alpha = a*pi/2;
tana2 = tan(alpha/2);
sina = sin(alpha);
f = ;
% chirp premultiplication
chrp = exp(-i*pi/N*tana2/4*(-2*N+2:2*N-2)'.^2);
f = chrp.*f;
% chirp convolution
c = pi/N/sina/4;
Faf = fconv(exp(i*c*(-(4*N-4):4*N-4)'.^2),f);
Faf = Faf(4*N-3:8*N-7)*sqrt(c/pi);
% chirp post multiplication
Faf = chrp.*Faf;
% normalizing constant
Faf = exp(-i*(1-a)*pi/4)*Faf(N:2:end-N+1);

function xint=interp(x)
% sinc interpolation
N = length(x);
y = zeros(2*N-1,1);
y(1:2:2*N-1) = x;
xint = fconv(y(1:2*N-1), sinc([-(2*N-3):(2*N-3)]'/2));
xint = xint(2*N-2:end-2*N+3);

function z = fconv(x,y)
% convolution by fft
N = length()-1;
P = 2^nextpow2(N);
z = ifft( fft(x,P) .* fft(y,P));
z = z(1:N);
</PRE>
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