assist 发表于 2006-5-8 14:04

利用杜哈美积分求速度、加速度

请问,怎样利用杜哈美积分求速度、加速度,(求杜哈美积分的导函数)而不是利用v=(s2-s1)/t;a=(v2-v1)/t这样的差分法。

感谢happy上次提供的杜哈美积分的源程序,向具体问问A,B是什么?还有怎样用duhamel积分求速度和加速度。不用差分法。

[ 本帖最后由 ChaChing 于 2010-3-15 15:59 编辑 ]

happy 发表于 2006-5-13 16:04

回复:(assist)happy:请问杜哈美积分

正弦余弦成分的幅值<BR><BR>已知位移表达式速度加速度表达式你不知道吗?

assist 发表于 2006-5-29 23:13

利用杜哈美积分求位移、速度和加速度

%单自由度系统适用,初始条件任意,比happy提供的适应性强。对于多自由度系统,正
%则化之后适用,加循环即可(有点修改,for t=0:dTaT end之间的不用改)。
clc; clear
n=1000; m=3; T=2; si=0.02; k=2700; w=30;
dTao=T/n; wD=w*(1-si^2)^0.5;
p2=; % p2=;
%%%%%%%%%%%%%%%杜哈美积分开始%%%%%%%%%%%%%%%%
x0=0; v0=0; j=1;
for t=0:dTaT
sysN=0; sysP=0;
%%%%%%%%%%%%位移\速度\加速度公用部分%%%%%%%%%%%%%%
for i=0:t/dTao
sysN=sysN+p2(i+1)*exp(si*i*dTao*w)*cos(wD*i*dTao)*dTao;
sysP=sysP+p2(i+1)*exp(si*i*dTao*w)*sin(wD*i*dTao)*dTao;
end
%%%%%%%%%%%%位移\速度\加速度公用部分%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%求位移%%%%%%%%%%%%%%%%%%%
sysA=exp(-si*w*t)*(x0*cos(wD*t)+(si*w*x0+v0)/wD*sin(wD*t));
sysB=exp(-si*w*t)/(m*wD)*(sin(wD*t)*sysN-cos(wD*t)*sysP);
x(j)=sysA+sysB;
%%%%%%%%%%%%%%%%%求位移%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%%%%%%%%%求速度%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%V=C+D+E+F%%%%%%%%%%%%%%%%%%
sysC=exp(-si*w*t)*(-x0*wD*sin(wD*t)-(si*w)^2*x0*sin(wD*t)/wD);
sysD=exp(-si*w*t)*(v0*cos(wD*t)-si*w*v0*sin(wD*t)/wD);
%%%%%%%%%%%%%%%E=G+H%%%%%%%%%%%%%%%%%%%%%%
sysG=sin(wD*t)*sysN;
sysH=-cos(wD*t)*sysP;
sysE=(sysN+sysP)*-si*w*exp(-si*w*t)/(m*wD);
%%%%%%%%%%%%%%%F=I+J+K+L%%%%%%%%%%%%%%%%%%
sysI=wD*cos(wD*t)*sysN;
sysJ=sin(wD*t)*p2(j)*exp(si*w*t)*cos(wD*t);
sysK=wD*sin(wD*t)*sysP;
sysL=-cos(wD*t)*p2(j)*exp(si*w*t)*sin(wD*t);
sysF=(sysI+sysJ+sysK+sysL)*exp(-si*w*t)/(m*wD);
v(j)=sysC+sysD+sysE+sysF;
%%%%%%%%%%%%%%%%%%%%%%%%%求速度%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%%%%%%%%%求加速度%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%%%sysdC%%%%%%%%%%%%%%%
sysdC1=-x0*wD^2*cos(wD*t)-(si*w)^2*x0*cos(wD*t);
sysdC=-si*w*sysC+exp(-si*w*t)*sysdC1;
%%%%%%%%%%%%%%%%%%%sysdD%%%%%%%%%%%%%%%
sysdD1=-v0*wD*sin(wD*t)-si*w*v0*cos(wD*t);
sysdD=-si*w*sysD+exp(-si*w*t)*sysdD1;
%%%%%%%%%%%%%%%%%%%sysdE%%%%%%%%%%%%%%%
sysdG=wD*cos(wD*t)*sysN+sin(wD*t)*p2(j)*exp(si*w*t)*cos(wD*t);
sysdH=wD*sin(wD*t)*sysP-cos(wD*t)*p2(j)*exp(si*w*t)*sin(wD*t);
sysdE=(si*w)^2*exp(-si*w*t)*(sysG+sysH)/(m*wD)-si*w*exp(-si*w*t)*(sysdG+sysdH)/(m*wD);
%%%%%%%%%%%%%%%%%%%sysdF%%%%%%%%%%%%%%%
sysdI=-wD^2*sin(wD*t)*sysN+wD*cos(wD*t)*p2(j)*exp(si*w*t)*cos(wD*t);
%%%%%%%%%%%%怎样考虑dP2,暂时取0%%%sysdJ%%%%%%%%%%
sysdJ1=wD*cos(wD*t)^2*p2(j)*exp(si*w*t);
sysdJ2=sin(wD*t)*0*exp(si*w*t)*cos(wD*t);
sysdJ3=sin(wD*t)*p2(j)*si*w*exp(si*w*t)*cos(wD*t);
sysdJ4=-wD*sin(wD*t)^2*p2(j)*exp(si*w*t);
sysdJ=sysdJ1+sysdJ2+sysdJ3+sysdJ4;
%%%%%%%%%%%%%%%%%%%sysdK%%%%%%%%%%%%%%%
sysdK=wD^2*cos(wD*t)*sysP+wD*sin(wD*t)*p2(j)*exp(si*w*t)*sin(wD*t);
%%%%%%%%%%%%怎样考虑dP2,暂时取0%%%sysdL%%%%%%%%%%
sysdL1=wD*sin(wD*t)^2*p2(j)*exp(si*w*t);
sysdL2=cos(wD*t)*0*exp(si*w*t)*sin(wD*t);
sysdL3=-cos(wD*t)*p2(j)*si*w*exp(si*w*t)*sin(wD*t);
sysdL4=-wD*cos(wD*t)^2*p2(j)*exp(si*w*t);
sysdL=sysdL1+sysdL2+sysdL3+sysdL4;
%%%%%%%%%%%%%%%%%sysdF%%%%%%%%%%%%%%
sysdF=-si*w*exp(-si*w*t)*(sysI+sysJ+sysK+sysL)/(wD*m)+exp(-si*w*t)*(sysdI+sysdJ+sysdK+sysdL)/(wD*m);
%%%%%%%%%%%%%%%%%acc%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
acc(j)=sysdC+sysdD+sysdE+sysdF;
%%%%%%%%%%%%%%%%%%%%%%%%%求加速度%%%%%%%%%%%%%%%%%%%%%%%%%
j=j+1;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%杜哈美积分完毕%%%%%%%%%%%%%%%%%%%%%%%%%
figure;
t=0:dTaT;
subplot(3,1,1);plot(t,x);grid on;
subplot(3,1,2);plot(t,v);grid on;
subplot(3,1,3);plot(t,acc);grid on;

[ 本帖最后由 ChaChing 于 2009-4-18 21:28 编辑 ]

realyyy 发表于 2006-12-7 09:48

好东西!我要研究研究!谢了!

lf51999 发表于 2007-6-11 17:26

好东西,收藏

cyk_2006 发表于 2007-10-27 10:28

好东西!我要研究研究!谢了!

hyl2323 发表于 2007-12-20 18:37

杜哈梅积分,求任意激励的响应,振动力学里的,我也编写过,你这个好难看懂!
这是我写的duhamel积分,完全是按照西安交大版《振动力学》上的公式写的,调试无误。
% duhamel      duhamel integral
% y=duhamel(x,h,fs)
% inputs:   x:analysed signal(vector)
%             h:impulse response
%             fs:frequency of sampling
% outputs:    y:duhamel integral of analysed signal x
function y=duhamel(x,h,fs)
    n=length(x);
    for i=1:n
      xx=x(1:i);
      hh=fliplr(h(1:i));
      temp=xx.*hh;
      y(i)=trapz(temp)*(1/fs);
    end

[ 本帖最后由 ChaChing 于 2009-4-18 21:26 编辑 ]

assist 发表于 2007-12-21 09:30

原帖由 hyl2323 于 2007-12-20 13:47 发表 http://www.chinavib.com/forum/images/common/back.gif
杜哈梅积分,求任意激励的响应,振动力学里的,我也编写过,你这个好难看懂!
我这个没有使用任何matlab系统函数,完全的一步一步下来的,如果你对duhamel积分公式研究一下是能看懂的。

hyl2323 发表于 2007-12-21 11:29

支持非matlab算法程序!

zeus1208 发表于 2009-1-27 00:08

好好学习一下

laughzha 发表于 2009-1-27 10:21

恩,好东西,楼主新年给大家送好礼啊:lol

上官楼 发表于 2009-4-18 14:47

:@) :@) :@) :@) 经典,就是不出结果啊!

wyx3710 发表于 2009-5-24 17:40

for t=0:dTaT
dTaT是什么意思?提示没定义呀?

liwang11 发表于 2009-6-1 16:46

支持!!!!

liwang11 发表于 2009-6-8 10:00

for t=0:dTaT
dTaT是什么意思?提示没定义呀?
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