大家看看这是怎么回事呢？
function imf = emd(x)% Empiricial Mode Decomposition (Hilbert-Huang Transform)
% imf = emd(x)
% Func : findpeaks
x=transpose(x(:));
imf = [];
while ~ismonotonic(x)
x1 = x;
sd = Inf;
while (sd > 0.1) | ~isimf(x1)
s1 = getspline(x1);
s2 = -getspline(-x1);
x2 = x1-(s1+s2)/2;
sd = sum((x1-x2).^2)/sum(x1.^2);
x1 = x2;
end
imf{end+1} = x1;
x = x-x1;
end
imf{end+1} = x;
% FUNCTIONS
function u = ismonotonic(x)
u1 = length(findpeaks(x))*length(findpeaks(-x));
if u1 > 0, u = 0;
else, u = 1; end
function u = isimf(x)
N= length(x);
u1 = sum(x(1:N-1).*x(2:N) < 0);
u2 = length(findpeaks(x))+length(findpeaks(-x));
if abs(u1-u2) > 1, u = 0;
else, u = 1; end
function s = getspline(x)
N = length(x);
p = findpeaks(x);
s = spline(,,1:N);
运行之后说x=transpose(x(:));有错误，什么意思呢？
我见过这个程序，我也用它算过东西，我在Matlab中试过transpose的用法，好像是把行向量换成列向量，或者是列向量换成行向量，我的数据x一开始就是列向量，所以没有出现那个问题……不知道对你有没有帮助？？
页:
[1]